Answer Given (2x – y z)2 Using identity, (x y z)2 = x2 y2 z2 2xy 2yz 2zx Here, x = 2x y = −y z = z (2x – y z) 2 = (2x) 2 (y) 2 z 2 (2 × 2x × y) (2× y × z) (2 × z × 2x)Apply the distributive property by multiplying each term of 2xy3z by each term of 2xy3z 4x^{2}6xzy^{2}3yz6xz3yz9z^{2} Combine 2xy and 2yx to get 0Expand\3(x6) expand\2x(xa) expand\(2x4)(x5) expand\(2x5)(3x6) expand\(4x^23)(3x1) expand\(x^23y)^3
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Expand (2x+y+3z)2-Expand the following (−x2y−3z) 2 Medium Solution Verified by Toppr (−x2y−3z) 2 =(−x) 2(2y) 2(−3z) 22(−x)(2y)2(2y)(−3z)2(−3yz)(−x) ∵(abc) 2=a 2b 2c 22ab2bc2ca =x 24yTherefore, it's a plane For instance, the set of all vectors orthogonal to (0,0,1) is the plane z = 0 Suppose x,y,z are positive real number such that x 2y 3z = 1 Find the maximum value of xyz2
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25x21 Final result 25x2 1 Step by step solution Step 1 Equation at the end of step 1 52x2 1 Step 2 Polynomial Roots Calculator 21 Find roots (zeroes) of F (x) = 2(x −3)2আমাদের বিনামূল্যের গণিত সমাধানকারী ব্যবহার করে ধাপে ধাপে করাAlgebra Examples Popular Problems Algebra Expand the Trigonometric Expression (2xy3z)^2 (2x − y 3z)2 ( 2 x y 3 z) 2 Rewrite (2x−y 3z)2 ( 2 x y 3 z) 2 as (2x−y 3z)(2x−y3z) ( 2 x y 3 z) ( 2 x y 3 z)
Answer(2xy3z)^2= 4x^2y^29z^24xy6yz12xz(3a2b)^3= 27a^318ab8b^3Stepbystep explanation1 (2xy3z)^2 = (2x)^2(y)^2(3z)^22(2x)(y)2(y)(3z)2(2x)( lobojulie lobojulie= {(x) ( 2y) ( 3z)} 2 = (x) 2 ( 2y) 2 ( 3z) 2 2(x) ( 2y) 2(2y)(3z)2(3z)(x) = x 2 4y 2 9z 2 4xy 12yz 6zx Ex 25, 4 Expand each of the following, using suitable identities (v) (2x 5y 3z)2 (2x 5y 3z)2 = ( (2x) 5y (3z) )2 Using (a b c)2 = a2 b2 c2 2ab 2bc 2ac
We take a = x, b = 2 y, c = 3 z in the expansion (a b c) 2 = a 2 b 2 c 2 2 a b 2 b c 2 c a We obtain (x 2 y 3 z) 2 = x 2 (2 y) 2 (3 z) 2 2 x (2 y) 2 (2 y) (3 z) 2 (3 z) x = x 2 4 Expression is (2x y 3z) 2 Formula used (a b c) 2 = a 2 b 2 c 2 2ab 2bc 2ca Calculation (2x y 3z) 2 ⇒ (2x) 2 (y) 2 (3z) 2 2(2x)(y) 2(y)(3z)Expand\3(x6) expand\2x(xa) expand\(2x4)(x5) expand\(2x5)(3x6) expand\(4x^23)(3x1) expand\(x^23y)^3
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